Pigs and sheep

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piyush_nitt: Master | Next Rank: 500 Posts; Posts: 424; Joined: Sun Dec 07, 2008 5:15 pm; Location: Sydney; Thanked: 12 times

by piyush_nitt » Thu Jan 01, 2009 5:37 pm

Here total combined population would be 1.2Sheep+1.2Pigs

and as Sheep = PIGS

therefore Total population = 2.4 PIGS/Sheeps

Correct me if I am wrong but i guess the figure should be divisible y 24 rather than 12. plz explain ?

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logitech: Legendary Member; Posts: 2134; Joined: Mon Oct 20, 2008 11:26 pmFollowed by: 25 members; Thanked: 237 times; GMAT Score:730

by logitech » Thu Jan 01, 2009 5:40 pm

piyush_nitt wrote:Here total combined population would be 1.2Sheep+1.2Pigs

Can also be expressed as:

AX+BX = X(A+B)

1.2 ( Sheep + Pigs )

1.2 ( PREVIOUS NUMBER )

This is why it is 1.2

and as Sheep = PIGS

therefore Total population = 2.4 PIGS/Sheeps

Correct me if I am wrong but i guess the figure should be divisible y 24 rather than 12. plz explain ?

LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"

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brb588: Senior | Next Rank: 100 Posts; Posts: 61; Joined: Mon Nov 17, 2008 11:35 pmFollowed by: 1 member; Thanked: 6 times

by brb588 » Thu Jan 01, 2009 9:29 pm

piyush_nitt wrote:Here total combined population would be 1.2Sheep+1.2Pigs

and as Sheep = PIGS

therefore Total population = 2.4 PIGS/Sheeps

Correct me if I am wrong but i guess the figure should be divisible y 24 rather than 12. plz explain ?

Again, the minimum number that satisfies the conditions set is 12 total. The smallest positive integer you can take 20 percent of that leaves you with a positive integer is five. Therefore:

Five pigs + five sheep + 5(.20) pigs = one pig + 5(.20) sheep = one sheep. That's a total of 12 animals. The answer choice has to be divisible by 12.

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Sachindh: Senior | Next Rank: 100 Posts; Posts: 37; Joined: Wed Sep 17, 2008 8:17 pm; Location: India; Thanked: 4 times

by Sachindh » Thu Jan 01, 2009 9:44 pm

The way I solved is

Lets say there are x pigs (even or odd) and so is the sheeps.
combining both will 2x
now 20% increase will 12/10 *2x

Now from answer choices, put 0 at the end of the answer choices. Now jus check which answer choice with last 2 digits divisible by 12. That should be correct answer. Therefore D.

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vivek.kapoor83: Legendary Member; Posts: 833; Joined: Mon Aug 04, 2008 1:56 am; Thanked: 13 times

by vivek.kapoor83 » Fri Jan 02, 2009 2:06 am

Brent,
I am not getting ur thing..if 1 animal is there,then we have to divide it by 6.......Pls explain

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maihuna: Legendary Member; Posts: 1578; Joined: Sun Dec 28, 2008 1:49 amFollowed by: 9 members; Thanked: 82 times; GMAT Score:720

by maihuna » Fri Jan 02, 2009 2:49 am

ans is D , here goes the pig theory

let number of ships = pigs = x
in 2004 2x
in 2005 1.2 *2x

Humm that way one ask fo rno shud be divisible by 24 but that is not necessary...nos can be taken as x/2 as well right?

D fits the bil only if 1.2 of some no is even.....right? why? we have added the no of ships to that of pigs what we get after dividing it by 1.2 see below fits the bill as that is divisible by 12, why 24 is not a must...the

5076/1.2 = 4230

so there were 4230/2 i.e. 2115 eac in 2004...huh..but is an O G q i doubt

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