Here total combined population would be 1.2Sheep+1.2Pigs
and as Sheep = PIGS
therefore Total population = 2.4 PIGS/Sheeps
Correct me if I am wrong but i guess the figure should be divisible y 24 rather than 12. plz explain ?
Pigs and sheep
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piyush_nitt
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logitech
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piyush_nitt wrote:Here total combined population would be 1.2Sheep+1.2Pigs
Can also be expressed as:
AX+BX = X(A+B)
1.2 ( Sheep + Pigs )
1.2 ( PREVIOUS NUMBER )
This is why it is 1.2
and as Sheep = PIGS
therefore Total population = 2.4 PIGS/Sheeps
Correct me if I am wrong but i guess the figure should be divisible y 24 rather than 12. plz explain ?
LGTCH
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brb588
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Again, the minimum number that satisfies the conditions set is 12 total. The smallest positive integer you can take 20 percent of that leaves you with a positive integer is five. Therefore:piyush_nitt wrote:Here total combined population would be 1.2Sheep+1.2Pigs
and as Sheep = PIGS
therefore Total population = 2.4 PIGS/Sheeps
Correct me if I am wrong but i guess the figure should be divisible y 24 rather than 12. plz explain ?
Five pigs + five sheep + 5(.20) pigs = one pig + 5(.20) sheep = one sheep. That's a total of 12 animals. The answer choice has to be divisible by 12.
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Sachindh
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The way I solved is
Lets say there are x pigs (even or odd) and so is the sheeps.
combining both will 2x
now 20% increase will 12/10 *2x
Now from answer choices, put 0 at the end of the answer choices. Now jus check which answer choice with last 2 digits divisible by 12. That should be correct answer. Therefore D.
Lets say there are x pigs (even or odd) and so is the sheeps.
combining both will 2x
now 20% increase will 12/10 *2x
Now from answer choices, put 0 at the end of the answer choices. Now jus check which answer choice with last 2 digits divisible by 12. That should be correct answer. Therefore D.
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vivek.kapoor83
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Brent,
I am not getting ur thing..if 1 animal is there,then we have to divide it by 6.......Pls explain
I am not getting ur thing..if 1 animal is there,then we have to divide it by 6.......Pls explain
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maihuna
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ans is D , here goes the pig theory
let number of ships = pigs = x
in 2004 2x
in 2005 1.2 *2x
Humm that way one ask fo rno shud be divisible by 24 but that is not necessary...nos can be taken as x/2 as well right?
D fits the bil only if 1.2 of some no is even.....right? why? we have added the no of ships to that of pigs what we get after dividing it by 1.2 see below fits the bill as that is divisible by 12, why 24 is not a must...the
5076/1.2 = 4230
so there were 4230/2 i.e. 2115 eac in 2004...huh..but is an O G q i doubt
let number of ships = pigs = x
in 2004 2x
in 2005 1.2 *2x
Humm that way one ask fo rno shud be divisible by 24 but that is not necessary...nos can be taken as x/2 as well right?
D fits the bil only if 1.2 of some no is even.....right? why? we have added the no of ships to that of pigs what we get after dividing it by 1.2 see below fits the bill as that is divisible by 12, why 24 is not a must...the
5076/1.2 = 4230
so there were 4230/2 i.e. 2115 eac in 2004...huh..but is an O G q i doubt
