grandh01 wrote:If x + y >0, is x > |y|?

If x+y>0 then either x, y or both will be positive. (at least one will positive and greater than zero)

(1) x > y
If x >y then x is positive. Y can be either negative or positive

If y>0 then x would have to be greater than absolute value of y for example x is 36 whereas y is 15.
If y<0 then it cannot be greater than the absolute value of x. For example if x is 36 then y cannot be less than -36 as it would not satisfy the x+y statement. Hence absolute value of y would be less than 36. Therefore x>abs y

(2) y <0
Since y <0 then x would be positive and absolute value of y cannot be less than x

Therefore both equations are sufficient on their own.

OA is D