Ans E
Let the ppl be a b and c

St 1

Total is 6
If a = 0 b = 2 c=4
or
a =1 b =0 c = 5
and other comb possible with some good for the question, some no

no suff

St 2
could be a number of possiblities

no suff

Together

same conditions in 1 apply

so E

ANS should be D

1) We know that a total of 6 tickets were sold so at least 1 member sold more that 2. Could be 6, 0, 0 or 2,2,2; either way one of the members sold more than 2.

2) If none of the three sold the same amount then the least one person sold 2. because the least possible set is 0,1,2. You can't have negative sales.

If they wanted to know if a specific member sold at least 2 it would be E, but since we only care that any one of the three sell at least 2 it is D.

OA is D,

But I still cannot understand Sattement#2. It says that No 2 of the members sold the same number of raffle tickets yesterday. 2 members can sell 0 or 1, aswell as 2 tickets. We do not know the total number of tickets sold.
Could anyone please explain why statement 2 is sifficient???

Thanks

now i get it!

Thanks, Ian!