$$If\ x>0,\ is\ \sqrt{x}>x?$$
Statement 1: x does not equal 1
$$i.e\ x\ne1$$
$$So,\ if\ x=2,\ \sqrt{2}>2$$
1.414 > 2 (this is not > than x=2)
$$Also\ if\ x=9,\ \sqrt{9}>9$$
3 > 9 (this is not > than x=9)
Therefore, statement 1 is NOT SUFFICIENT.

Statement 2:
$$x\sqrt{x}>x^2$$
$$\sqrt{x}>\frac{x^2}{x}$$
$$\sqrt{x}>x^{ }$$
$$This\ answers\ the\ target\ question\ that\ \sqrt{x}>x$$
Therefore, statement 2 is SUFFICIENT.

Since only statement 2 is SUFFICIENT, then option B is the correct answer.