melguy wrote:Please help me with the problem. I understand that we need to apply the formula DIVIDEND = (DIVISOR X QUOTIENT) + REMAINDER but I am unable to solve. Thanks
A number X when divided by 289 leaves 18 as the remainder. The same number when divided by 17 leaves Y as the remainder. Find Y.
a 1
b 2
c 11
d 20
e 23
A number X when divided by 289 leaves 18 as the remainder.
In other words, X is 18 more than a multiple of 289.
Translated into math:
X = 289a + 18, where a is an integer greater than or equal to 0.
If a = 0, then X = 289*0 + 18 = 18.
If a = 1, then X = 289*1 + 18 = 307.
If a = 2, then X = 289*2 + 18 = 596.
Note the following:
The LEAST POSSIBLE VALUE Is the REMAINDER ITSELF (18).
To generate other possible values for X, just add the divisor (289) to each resulting value:
X = 18, 18+289 = 307, 307+289 = 596...
The same number when divided by 17 leaves Y as the remainder.
The least possible value for X is 18.
If X = 18, then X/17 = 18/17 = 1 R 1.
Since R=1, the correct answer is
A.
Other remainder problems:
https://www.beatthegmat.com/positive-int ... 96845.html
https://www.beatthegmat.com/remainder-of ... 54799.html
https://www.beatthegmat.com/remainder-t115616.html
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