jainrahul1985 wrote:If -2x > 3y, is x negative?
(1) y > 0
(2) 2x + 5y - 20 = 0
OA D
1)-2x > 3y
=> x < -(3/2)y
Also y > 0
Therefore x has to be negative
Experts please help me understand why Statement 2 is sufficient
Statement 1: y > 0
Since y > 0, 3y > 0.
Linking together -2x > 3y and 3y > 0, we get:
-2x > 3y > 0
-2x > 0
x < 0.
Sufficient.
Statement 2: 2x + 5y - 20 = 0
Thus, 5y-20 = -2x.
Substituting 5y-20 for -2x in -2x > 3y, we get:
5y-20 > 3y
2y > 20
y > 10.
We saw in statement 1 that y > 0 implies that x < 0.
Sufficient.
The correct answer is
D.
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