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Coordinate geometry

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by nakul_anand » Sun May 09, 2010 10:37 am
Is B the answer?
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by iamseer » Sun May 09, 2010 10:42 am
IMO B

drop a perpendicular from B on AD.Let that point be X. BX has length of 3. AX =3 b'cos 45-45-90 triangle. Also, AB =3sqrt2
also, BC=8-3=5

therefore perimeter = 2*(5+3sqrt2) = 10 + 6sqrt2

HTH!!
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by dkumar.83 » Sun May 09, 2010 10:42 am
I dont know the answer actually. If you have solved it, let me know the calculation.
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by harshavardhanc » Sun May 09, 2010 10:45 am
nakul_anand wrote:Is B the answer?
IMO B

as <BAD is 45, coordinates of B are (3,3) BA becomes 3 V2 and BC becomes 5. Hence, perimeter is 6 V2 + 10 .
Regards,
Harsha
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by dkumar.83 » Sun May 09, 2010 10:45 am
Thanks man.
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