By Pythagoras Theorem,sud21 wrote:
In triangle ABC, AC = √(x² + x²) = x√2
In triangle ACD, AD = √[x² + (x√2)²] = √(x² + 2x²) = x√3
In triangle ADE, AE = √[x² + (x√3)²] = √(x² + 3x²) = 2x
Therefore, perimeter of polygon ABCDE = AE + ED + DC + CB + BA = 2x + x + x + x + x = 6x
The correct answer is C.
