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Question 9 (nov.17th)

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Question 9 (nov.17th)

by bacali » Mon Nov 17, 2008 1:06 pm
The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1) x > y
(2) 100xy < x – y

OA: B
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by lachlanc » Mon Nov 17, 2008 2:08 pm
Are you sure statement II is copied correctly? I think the question would make more sense if it was xy/100 < x - y
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by rtfact » Mon Nov 17, 2008 5:06 pm
Statement 1 does not help much. Suppose there was an increase by 1/2 and then a decrease by a 1/3 -> the rent would not change. So if the increase would have been a bit smaller - 1/3-0.0001 then the rent in 99 would be higher than in 97, and if the increase would have been a bit higher- 1/3+0.0001 then the rent in 99 would be lower than in 97.

we have to determine whether
r<r(100+x)(100-y)/100*100=r(1+(x-y)100-xy/100*100)
or
0<(x-y)100-xy/100*100

while remembering that x,y>0
from statement 2 we can conclude that 0<xy-xy/100*100 is true. hence B.
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by 4meonly » Sun Nov 23, 2008 3:37 am
The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?
(1) x > y
(2) 100xy < x – y
Can anybody confirm that statement 2 is correct?
Otherwise I do not understand rtfact's solution


rtfact wrote:Statement 1 does not help much. Suppose there was an increase by 1/2 and then a decrease by a 1/3 -> the rent would not change. So if the increase would have been a bit smaller - 1/3-0.0001 then the rent in 99 would be higher than in 97, and if the increase would have been a bit higher- 1/3+0.0001 then the rent in 99 would be lower than in 97.
we have to determine whether
r<r(100+x)(100-y)/100*100=r(1????+(x-y)100-xy/100*100)
or
0<(x-y)100-xy/100*100
while remembering that x,y>0
from statement 2 we can conclude that 0<xy-xy/100*100 is true. hence B.
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by xyzabc123 » Sun Nov 23, 2008 8:54 pm
I think (2) should be xy < 100(x-y)
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