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Please help me with the solution

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Please help me with the solution

by [email protected] » Wed Jan 29, 2014 7:57 am
Anne and Beth will participate in a sack race (In a sack race, people hop to reach the finish line). In the time that Anne takes 3 hops, Beth takes 4 hops but the distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops. What is the ratio of Anne's speed: Beth's speed?


3 : 5


12 : 20


15 : 16


1 : 1


5 : 3
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by Patrick_GMATFix » Wed Jan 29, 2014 8:23 am
speed/rate = distance/time.
The distance covered by Anne in 4 hops is equal to the distance covered by Beth in 5 hops.
Plug-In: If each of Anne's hops covers a distance of 5 inches, then each of Beth's will cover a distance of 4 inches.
In the time that Anne takes 3 hops, Beth takes 4 hops
Since according to our plug-ins above, Anne covers a distance of 5 in. and Beth 4 in. with each hop, this can be rephrased as "in the time that Anne covers a distance of 3*5=15 inches, Beth covers 4*4=16 inches.

Now we have the rates. Anne's speed = 15 in./unit of time. Beth's speed = 16 in./unit of time. The ratio we want is Anne:Beth = 15:16. Answer is C
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