I think you mean "sqrt" (not "underroot")[email protected] wrote:A circle with a diameter 10 is centered on the origin, which of the following points are on the circle
a)(5,0)
b)(5,5)
c)(-3,4)
d) (1,-2sqrt6)
e) (-2, sqrt6)
i think that also D is correct:Brent@GMATPrepNow wrote:I think you mean "sqrt" (not "underroot")[email protected] wrote:A circle with a diameter 10 is centered on the origin, which of the following points are on the circle
a)(5,0)
b)(5,5)
c)(-3,4)
d) (1,-2sqrt6)
e) (-2, sqrt6)
I have edited the question accordingly.
NOTE: This question is un-GMAT-like because it allows for more than 1 correct answer. That said, it could possibly appear in the IR section.
Okay, the first thing to recognize is that the circle has radius 5.
If a circle of radius is centered on the origin, any point (x,y) on the circle must be such that x^2 + y^2 = 5^2. Here's why . . .
Let's take a point on the circle, say (-3, 4), notice that we can create a right triangle.
Since we have a right triangle, Pythagoras tells us that (-3)^2 + 4^2 = 5^2
In general, any point (x,y) on the circle must be such that x^2 + y^2 = 5^2
Now we'll check the answer choices.
a)(5,0): does 5^2 + 0^2 = 5^2? YES! So, this point is on the circle.
b)(5,5): does 5^2 + 5^2 = 5^2? NO So, this point is not on the circle.
c)(-3,4): does (-3)^2 + 4^2 = 5^2? YES! So, this point is on the circle.
d) (1,-2sqrt6): does 1^2 + (-2sqrt6)^2 = 5^2? NO So, this point is not on the circle.
e) (-2, sqrt6): does (-2)^2 + (sqrt6)^2 = 5^2? NO So, this point is not on the circle.
Answers: [spoiler]A & C[/spoiler]
Cheers,
Brent
Good catch!v1nc3nz0 wrote:i think that also D is correct:Brent@GMATPrepNow wrote:I think you mean "sqrt" (not "underroot")[email protected] wrote:A circle with a diameter 10 is centered on the origin, which of the following points are on the circle
a)(5,0)
b)(5,5)
c)(-3,4)
d) (1,-2sqrt6)
e) (-2, sqrt6)
I have edited the question accordingly.
NOTE: This question is un-GMAT-like because it allows for more than 1 correct answer. That said, it could possibly appear in the IR section.
Okay, the first thing to recognize is that the circle has radius 5.
If a circle of radius is centered on the origin, any point (x,y) on the circle must be such that x^2 + y^2 = 5^2. Here's why . . .
Let's take a point on the circle, say (-3, 4), notice that we can create a right triangle.
Since we have a right triangle, Pythagoras tells us that (-3)^2 + 4^2 = 5^2
In general, any point (x,y) on the circle must be such that x^2 + y^2 = 5^2
Now we'll check the answer choices.
a)(5,0): does 5^2 + 0^2 = 5^2? YES! So, this point is on the circle.
b)(5,5): does 5^2 + 5^2 = 5^2? NO So, this point is not on the circle.
c)(-3,4): does (-3)^2 + 4^2 = 5^2? YES! So, this point is on the circle.
d) (1,-2sqrt6): does 1^2 + (-2sqrt6)^2 = 5^2? NO So, this point is not on the circle.
e) (-2, sqrt6): does (-2)^2 + (sqrt6)^2 = 5^2? NO So, this point is not on the circle.
Answers: [spoiler]A & C[/spoiler]
Cheers,
Brent
(1,-2sqrt6): does 1^2 + (-2sqrt6)^2 = 1^2 + (-2)*(-2)*(sqrt6)*(sqrt6)= 1 + 4 * 6 = 25 = 5^2
Am i wrong ?
