Question # 28
Area of a right-angled triangle is doubled while the base is reduced to its half. What % increase occurs in its height?
(A) 300%
(B) 370%
(C) 150%
(D) 400%
(E) 510%
The Way I tried to solve this is by plug in numbers
Let base = 2 ,height = 4
Area= 1/2*B*H
Area=4
Now I double this Area = 8
Reduce base by 1/2 = 1
Height --- 8=1/2 * h H= 16
New Height to Old Height 16/4 which is 4 = 400% (D)? seems pretty straight forward...am I missing something here?
Real Answer is A can someone explain?
Area of a right-angled triangle is doubled while the base is reduced to its half. What % increase occurs in its height?
(A) 300%
(B) 370%
(C) 150%
(D) 400%
(E) 510%
The Way I tried to solve this is by plug in numbers
Let base = 2 ,height = 4
Area= 1/2*B*H
Area=4
Now I double this Area = 8
Reduce base by 1/2 = 1
Height --- 8=1/2 * h H= 16
New Height to Old Height 16/4 which is 4 = 400% (D)? seems pretty straight forward...am I missing something here?
Real Answer is A can someone explain?
