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by Rahul@gurome » Thu Aug 12, 2010 4:09 pm
Jinglander wrote:If ab=x and a/b=y and ab does not equal 0 then what is a^2-b^2. How do you get the answer

It is x(y-1)(y+1)/y
Multiplying ab=x and a/b=y we get, a^2 = xy
ab=x implies a^2.b^2 = x^2 or b^2 = x^2/a^2 = x^2/xy = x/y
So, a^2-b^2 = xy - x/y = (x.y^2 - x)/y = x(y^2 -1)/y = x(y-1)(y+1)/y
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