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Permo Combo continues 12

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by maihuna » Mon Aug 10, 2009 8:29 am
Find the number of arrangements which can be made out of the letters of the world "algebra" without altering the relative positions of vowels and consonants.

26
36
72
75
85
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by real2008 » Mon Aug 10, 2009 9:17 am
it must be 72
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by maihuna » Mon Aug 10, 2009 10:16 am
real2008 wrote:it must be 72
how?
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Re: Permo Combo continues 12

by real2008 » Mon Aug 10, 2009 10:23 am
maihuna wrote:Find the number of arrangements which can be made out of the letters of the world "algebra" without altering the relative positions of vowels and consonants.

26
36
72
75
85

vowels:V
consonants:C

VCCVCCV

keeping V and C position relatively same,

(3!/2)[div by 2 for two 'a's are there and to eliminate redundancy]x4!=72
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by prindaroy » Mon Aug 10, 2009 11:18 am
A_ _ E _ _ A

for vowels = 3!/2! = 3

for consonants = 4!

so 3*4! = 72
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