- sanju09
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In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular dropped from B, meets the side AC at D. A circle of radius BD (with center B) is drawn. If the circle cuts AB and BC at P and Q respectively, then AP:CQ is equal to
(A) 4:1
(B) 3:1
(C) 1:1
(D) 3:2
(E) 3:8
(A) 4:1
(B) 3:1
(C) 1:1
(D) 3:2
(E) 3:8
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com












