2x+3y+4=0，4x+6y+a=0; what is the value of a when both functions have more than one solution?
OA 8
OA 8
Ans 8 sounds right to me.
Ok so we have two equations
First 2x+3y+4=0
Second 4x+6y+a=0
We have been asked to calculate the value of X so we need to simplify the equations by trying to cancel out variables x and y somehow.
Now if i multiply first equation by 2 then the equation becomes
The first equation was 2x+3y+4=0; after multiplying by 2 it becomes
4x + 6y + 8 = 0;
Now if we subtract equation 2 from our new equation one we get
4x + 6y + 8 = 0 ------ eq 1
4x + 6y + a = 0 ---- eq 2
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0 + 0 + 8-a = 0 which gives us a = 8.
