BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

BTG quistion

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Legendary Member
Posts: 759
Joined: Mon Apr 26, 2010 10:15 amFollowed by: 3 members
Thanked: 85 times

by clock60 » Sun May 15, 2011 3:14 am
hi i hope that the answer is D
second st is easier
(2)if x=60, then angle BCD=120, and angle CBD=30, thus triangle BCD is isosceles. and BC=6.
so suff
(1) with brute force, if you know 2 sides of triangle and angle between them. you can calculate the last side using cosine theorem, no need to calculate, but simply to know
BC^2=CD^2+BD^2-2*CD*BD*cos30, now know that BD=6*3^1/2, CD=6, and cos 30 is fixed value ((3^1/2)/2)
so you can find BC
also suff
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Tue Apr 19, 2011 7:39 pmFollowed by: 2 members
Location: Singapore
Thanked: 6 times

by abhi0697 » Sun May 15, 2011 9:34 pm
Agree with D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 516
Joined: Mon Nov 02, 2009 6:42 amFollowed by: 1 member
Location: Mumbai
Thanked: 14 times
GMAT Score:710

by ankurmit » Mon May 16, 2011 7:10 am
clock60 wrote:hi i hope that the answer is D
second st is easier
(2)if x=60, then angle BCD=120, and angle CBD=30, thus triangle BCD is isosceles. and BC=6.
so suff
(1) with brute force, if you know 2 sides of triangle and angle between them. you can calculate the last side using cosine theorem, no need to calculate, but simply to know
BC^2=CD^2+BD^2-2*CD*BD*cos30, now know that BD=6*3^1/2, CD=6, and cos 30 is fixed value ((3^1/2)/2)
so you can find BC
also suff
thanks
--------
Ankur mittal
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1