PGMAT wrote:Linda and Angela contract to paint a neighbor's house. Even though Linda spends 50% more time painting the house than Angela, each receives a payment of m dollars when the work is completed. If Angela decides to pay Linda n dollars so that they would have received the same compensation per hour worked, what is n in terms of m?
1/2m
1/3m
1/4m
1/5m
1/6m
Can some help me solve this algebraically?
Thanks
D
I would plug in values for the hourly rate and for the time worked.
Let hourly rate = $2 per hour.
Let time for Angela = 2 hours.
Since Linda works 50% longer, time for Linda = (1.5)*2 = 3 hours.
Total pay = (rate) * (total time) = 2*(2+3) = $10.
Since each received m dollars in advance, m = 10/2 = $5.
Since Angela should earn 2*2 = $4, she must give Linda n = 5-4 = $1.
The question asks for the value of n=1. Now we plug m=5 into all the answer choices to see which yields our target of 1.
Only answer choice D works:
(1/5)*m = 1/5 * 5 = 1.
The correct answer is
D.
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