Hi Brent - the below does not make sense to me - help I am confused. (when i pick smart numbers)
Let us take your case - RS 5 be Brand A (apples)
For Brand A - total quantity is say 10 apples. Therefore total cost = Rs 50

Brand B : Rs 7 per apple. Since the question states similar quantity, let us say 10 apples of Brand B were purchased as well
For Brand B - Total quantity = 10 and total price/cost= Rs 7 X 10 = Rs 70

Now Total Amount spent for both brands = 50 + 70 = 120 and Total Quantity is 20 apples.

If the person sells them for Rs 6 each - then total amount of revenue = 16 X 20 = RS 120

It breaks even - so to me there is no profit or loss.

Please advise
Thanks
Subhakam

Hi Subhakam, 5 and 7 are apples which can be bought for a rupee and not the prices per apple.

Similarly 6 apples can be sold for a rupee and it is not that an apple costs rupees 6.

Hope this makes sense!!!

sohailmbaprep wrote:Mr X buys some apples at 5 per rupee from one trader ,and a similar quantity at 7 per rupee from another trader.He mixes both the varieties, and sells the whole at 6 per rupee.What is the profit or loss % that he makes ?

is it a mixture problem ?? how can i solve this

Let the number of apples purchased from each trader = the LCM of 5, 6 and 7 = 210.

Trader one:
At 5 apples per rupee, the cost of 210 apples = 210/5 = 42 rupees.

Trader two:
At 7 apples per rupee, the cost of 210 apples = 210/7 = 30 rupees.

Total number of apples = 210+210 = 420.
Total cost = 42+30 = 72.

Revenue:
Since 6 apples earn 1 rupee, the revenue for 420 apples = 420/6 = 70 rupees.

Loss = cost - revenue = 72-70 = 2.
Percent loss = loss/cost * 100 = 2/72 * 100 = 2.77%.