ska7945 wrote:5. One-forth of a solution that was 10 percent sugar by weight was replaced by a second solution, resulting in a solution that was 16% sugar by weight. The second solution was that percent sugar by weight?
1)34% 2)24% 3)22% 4)18% 5)8.5%
Let's let x = the amount of solution, which initially contains 10% sugar. We remove one-fourth of that solution (.25x), which has 10% sugar. Then we replace that .25x with a solution of unknown percentage (p) of sugar. These actions result in our still having x amount of solution, but now with 16% sugar. We can summarize this in the following equation:
x(0.10) - (0.25x)(0.10) + (0.25x)(p) = x(0.16)
0.10x - 0.025x + 0.25xp = 0.16x
100x - 25x + 250xp = 160x
250xp = 85x
p = 85/250 = .34
Thus, the second solution was 34% sugar by weight.
Answer:
A
