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If a is a positive integer, and if the units digit of a^2...

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by swerve » Fri Dec 15, 2017 1:11 pm
If a is a positive integer, and if the units digit of a^2 is 9 and the units digit of (a+1)^2 is 4, what is the units digit of (a+2)^2?

A. 1
B. 3
C. 5
D. 6
C. 14

The OA is A.

Experts, i need your help with this PS question, please!

Can I say that a=3? I don't understand it, How can I solve this question? Thanks!
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by GMATGuruNY » Fri Dec 15, 2017 1:18 pm
swerve wrote:If a is a positive integer, and if the units digit of a^2 is 9 and the units digit of (a+1)^2 is 4, what is the units digit of (a+2)^2?

A. 1
B. 3
C. 5
D. 6
C. 14
Let a=7, with the result that a² = 7² = 49 and that (a+1)² = (7+1)² = 8² = 64.
In this case:
(a+2)² = (7+2)² = 9² = 81.
Thus, the units digit of (a+2)² is 1.

The correct answer is A.
Can I say that a=3?
If a=3, then (a+1)² = (3+1)² = 4² = 16, which violates the condition that (a+1)² has a units digit of 4.
Thus, it is not possible that a=3.
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by Scott@TargetTestPrep » Mon Sep 23, 2019 4:38 pm
swerve wrote:If a is a positive integer, and if the units digit of a^2 is 9 and the units digit of (a+1)^2 is 4, what is the units digit of (a+2)^2?

A. 1
B. 3
C. 5
D. 6
C. 14
Since the units digit of a^2 is 9, the units digit of a is either 3 or 7. However, since the units digit of (a+1)^2 is 4, we see that the units digit of a must equal 7, since then the units digit of a + 1 is 8 and 8^2 = 64 (had the units digit of a been 3, then the units digit of a + 1 would have been 4, but 4^2 = 16). Thus, the units digit of a + 2 is 9, and since 9^2 = 81, the units digit of (a + 2)^2 is 1.

Answer: A

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