Since BE and CD are parallel, the angles where BE and CD intersect AC are the same, and the angles where BE and CD intersect AD are the same.
Triangles BAE and CAD also share angle A.
Clearly since the three angles of triangle BAE are the same as the three angles of triangle CAD, BAE and CAD are similar triangles.
The lengths of corresponding sides of similar triangles are all in the same ratio.
So if BC = AB, then AC = 2AB and all the sides of CAD are twice the length of the corresponding sides of BAE.
Since AE = 4, AD = 8.
Since CD = 10, BE = 5
CA = 3 + 3 = 6
AD = 8
CD = 10
So CAD is a 6-8-10 (multiple of a 3-4-5) right triangle.
BA = 3
AD = 4
BD = 5
BAD is a 3-4-5 right triangle.
To find the area of a right triangle, you can simply multiply the lengths of the two perpendicular sides and divide by 2.
Area CAD = (6 x 8)/2 = 24
Area BAE = (3 x 4)/2 = 6
To get the area of the trapezoid, subtract area BAE from area CAD.
24 - 6 = 18
The correct answer is B.














