Let r=2 and x=3.datonman wrote:In the sequence, r, s, t, if each term after the first is x more than the previous term, what is the average of r, s, and t in terms of r and x?
A) r + x
B) r + x/3
C) r + 2x/3
D) r+x/3
E) 3(r+x)
Since each term is x=3 more than the previous term, we get:
r, s, t = 2, 5, 8.
Average of r, s and t = (2+5+8)/3 = 5. This is our target.
Now plug r=2 and x=3 into the answers to see which yields our target of 5.
Only A works:
r+x = 2+3 = 5.
The correct answer is A.
