Avg = 70
Sum = 70*5 = 350
To maximize the smallest integer, minimize the largest ones.

So, the sequence would look like a,b,84,84,84
So, a+b = 350-84*3 = 98
Max a will be when a = b. So, a = 49

givemeanid wrote:Avg = 70
Sum = 70*5 = 350
To maximize the smallest integer, minimize the largest ones.

So, the sequence would look like a,b,84,84,84
So, a+b = 350-84*3 = 98
Max a will be when a = b. So, a = 49

wow.. That's one heck of a solution..Thanks for helping out..BTW, how is your application process going on..

Since I was slacking a week or two before my test, I am catching up at work right now. The apps are going slower than I thought... but I have plenty of time for Round 2 since I would not be able to put the best app together for Round 1.

Thanks for asking.

Givemeanid, I am having some doubt! Refer your approach below -

Avg = 70
Sum = 70*5 = 350
To maximize the smallest integer, minimize the largest ones.

So, the sequence would look like a,b,84,84,84
So, a+b = 350-84*3 = 98
Max a will be when a = b. So, a = 49

Now my question is why you took a and b as unknown? I mean that I can only take a as unknown and the equation becomes -
a = 350 - 84*4 = 14
OR
The sequence would look like a,b,C,84,84
a + b + c = 350 - 84 * 2 = 168
Max a will be when a = b = c. So, a = 84
By this I want to say that I really did not find the logic you implemented here. Can you please make me understand?

Hi, let me try to explain.
Let the numbers be A, B, C, D & E. (in increasing numerical value order)
we know the average (mean) is 70 hence
A+B+C+D+E = 70*5 = 350
Median for an odd cardianlity set is the central element (middle value)
hence C = 84
& we have to identify the maximum value for A.
for this
1. B +D + E has to be minimum.
2. B is greater than or equal to A
3. D & E are greater than or equal to C (=84)
Hence for A to achieve maximum, B, D, E have to asssume minimum possible, i.e., B = A & D=E=C=84
Thus solve & get A = 49.

Let me know if there are still some doubts about this approach.

Ohhhhh! Now I understood. Thank u, Bharat. Its a really nice problem to solve then. Actually I have never faced this kind of prob earlier. A good learning for me.