S1 = 6 = 6*1ajdjmba wrote:If S is the infinite sequence S1 = 6, S2 = 12, ..., Sn = Sn-1 + 6,..., what is the sum of all terms in the set {S13, S14, ..., S28}?
S2 = 12 = 6*2
S3 = 18 = 6*3
Hence, Sn = 6n
Therefore, (S13 + A14 + ... + S28) = (6*13 + 6*14 + ... + 6*28) = 6*(13 + 14 + ... + 28)
Now, from 13 to 28 there are 16 integers and their mean is (13 + 28)/2
Hence, (13 + 14 + ... + 28) = 16*(13 + 28)/2 = 8*41 = 328
Therefore, required sum = 6*328 = 1968
The correct answer is D.












