- bml1105
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When both floodgates A and B are open, a reservoir drains in 3 1/3 days. If floodgate A alone drains the reservoir in 10 days, how many days does it take floodgate B alone to drain the reservoir?
(A) 4
(B) 5
(C) 6 2/3
(D) 10
(E) 12
OA: B
I solved it the following way. The book explained it differently and I just want to make sure my method is correct and I didn't just get lucky.
A ---> R = 1/10 T = 10 days W = 1 reservoir so 1/10 x 10 = 1
A&B ---> R x (10/3) = 1 so AB rate = 3/10
find B ---> AB Rate - A Rate = B Rate so 3/10 - 1/10 = 2/10
Time for B = T ---> (2/10) x T = 1 so T = (10/2) = 5 days
(A) 4
(B) 5
(C) 6 2/3
(D) 10
(E) 12
OA: B
I solved it the following way. The book explained it differently and I just want to make sure my method is correct and I didn't just get lucky.
A ---> R = 1/10 T = 10 days W = 1 reservoir so 1/10 x 10 = 1
A&B ---> R x (10/3) = 1 so AB rate = 3/10
find B ---> AB Rate - A Rate = B Rate so 3/10 - 1/10 = 2/10
Time for B = T ---> (2/10) x T = 1 so T = (10/2) = 5 days


















