What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y = 3/4*x - 3?
A) 1.4
B) sqrt (2)
C) 1.7
D) sqrt (3)
E) 2.0
A) 1.4
B) sqrt (2)
C) 1.7
D) sqrt (3)
E) 2.0
My answer is 1.4
The equation of the line will be 3x - 4y - 12 = 0.
This crosses the x and y axis at (0,-3) and (4,0).
the circle has a radius of 1.
So it is closest to the given line when, a perpendicular is drawn to the line, which passes through the origin.This distance of the line from the origin is
12 / sqrt (9 + 16) which is 2.4
Length of perpendicular from origin to line ax +by + c = 0 is mod (c / sqrt (a^2 + b^2)
The radius is 1 unit.
So the shortest distance is 2.4 - 1 unit = 1.4 units
hope its clear
