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2, 2, 7 and 9 be arranged

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by sanju09 » Wed Feb 29, 2012 12:12 am
In how many different ways can the digits 2, 2, 7 and 9 be arranged, so that there is at least one 2 between 7 and 9 always?
A. 3
B. 4
C. 6
D. 9
E. 12
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by Anurag@Gurome » Wed Feb 29, 2012 12:40 am
sanju09 wrote:In how many different ways can the digits 2, 2, 7 and 9 be arranged, so that there is at least one 2 between 7 and 9 always?
A. 3
B. 4
C. 6
D. 9
E. 12
The possible arrangements are:

Case 1: When 1st digit is 2.
2729, 2927

Case 2: When 1st digit is 7.
7292, 7229

Case 2: When 1st digit is 9.
9272, 9227

Therefore, required number of ways = 2 + 2 + 2 = 6

The correct answer is C.
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