M7MBA wrote:Which of the following is equivalent to $$\frac{x+y}{3}-\frac{x-y}{4}?$$
$$A.\ \frac{x+y}{12}$$
$$B.\ \frac{7x+y}{12}$$
$$C.\ \frac{7x-y}{12}$$
$$D.\ \frac{7y+x}{12}$$
$$E.\ \frac{7y-x}{12}$$
Let x=2 and y=1, with the result that (x+y)/3 - (x-y)/4 = 1 - 1/4 = 3/4.
The correct answer must yield 3/4 when x=2 and y=1.
Only D works:
(7y+x)/12 = (7*1 + 2)/12 = 9/12 = 3/4
The correct answer is
D.
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