BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Geometry

Expert replies
by knight247 » Tue Dec 13, 2011 6:04 am
OA is D

I solved it in this manner... Point F with co-ordinates 2,-1 is the midpoint of two points... i.e.
x1+x2/2=2 or x1+x2=4 and y1+y2/2=-1 or y1+y2=-2. I then checked which answer choices meet this requirement. I narrowed it down to B and D. But am unable to go any further. Hoping to get some detailed explanations. Cheers.
Attachments
ims.JPG
Join the discussion
Source: — Problem Solving |

by Elena89 » Tue Dec 13, 2011 6:30 am
To save time, one can tell from just looking at the answer choices.

Its obvious from the figure that if y-coordinate of F lies in the negative y-axis then B being further below would also lie in the -ve y-axis, so this cancels out the first 3 answer choices.
Now again looking at the coordinates of A in the answer choices (D) and (E), we know that if F has negative y-coordinate of -1 then that of point A must be greater than -1 (i.e in the positive y-axis)
And answer choice (D) solves that issue. so that's the correct one..
Join the discussion

by GMATGuruNY » Tue Dec 13, 2011 6:53 am
knight247 wrote:OA is D

I solved it in this manner... Point F with co-ordinates 2,-1 is the midpoint of two points... i.e.
x1+x2/2=2 or x1+x2=4 and y1+y2/2=-1 or y1+y2=-2. I then checked which answer choices meet this requirement. I narrowed it down to B and D. But am unable to go any further. Hoping to get some detailed explanations. Cheers.
ALWAYS LOOK AT THE ANSWER CHOICES.

Since B and D include the same two coordinate pairs, just in reverse order, the ordering in the answer choices must reflect the ordering in the question: the first coordinate pair in each answer choice is B, the second A.
Since the x coordinate of F is 2, the x coordinate of B must be greater than 2, and the x coordinate of A must be less than 2.
Only answer choice D works: (6,-3) and (-2,1).

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by GmatMathPro » Tue Dec 13, 2011 7:01 am
When the midpoints of the sides of triangles are connected like this, two important things happen. 1) The segment connecting the midpoints is parallel to the third side. 2) The segment connecting the midpoints is half the length of the third side. These properties are a result of similar triangles that can be proved by the ~SAS similarity postulate.

Note that going from point D(1,3) to point E(-3,5) you go up 2 units and 4 to the left. From the abovve we can deduce that FA=ED and that FA is parallel to ED. We can preserve these two properties only if we also go up 2 and left 4 to get to A. F is at (2,-1), so going up 2 and left 4 puts you at (-2,1) for point A. Through similar logic we can get to point B by going right 4 and down 2 from (2,-1) to get to (6,-3) for point B.

Thus, the answer is D
knight247 wrote:OA is D

I solved it in this manner... Point F with co-ordinates 2,-1 is the midpoint of two points... i.e.
x1+x2/2=2 or x1+x2=4 and y1+y2/2=-1 or y1+y2=-2. I then checked which answer choices meet this requirement. I narrowed it down to B and D. But am unable to go any further. Hoping to get some detailed explanations. Cheers.
[spoiler][/spoiler]
Pete Ackley
GMAT Math Pro
Free Online Tutoring Trial
Join the discussion