I could not find the solution of the question attached.
This is from GMATPrep
This is from GMATPrep
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- Circle Question
Thanks,
Ankur Tyagi
Ankur Tyagi
OP = OQ ( assume O has coodinates(0,0) )
Distance betwwen two points
(1-0)^2 + (-sqrt3-0)^2 = (s-0)^2 + (t-0)^2
1+3 = s^2+t^2
s^2+t^2 = 4 ---------(1)
Since the lines are perpendicular to each other, product of slopes = -1
(Y2-Y1)/(X2-X1) * (Y2-Y1)/(X2-X1)= -1
[(1-0)/(-sqrt3-0)]*[(t-0)/(s-0)] = -1
t/s = sqrt3
t = s*sqrt3
From (1), s^2 + 3s^2 = 4
s^2 = 1
AS S is in 1st quadrant s=1
hope this helps.
