BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

I need help... quantitative

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Thu Dec 18, 2008 9:51 pm
Location: San Diego, Ca

I need help... quantitative

by properz » Wed Aug 12, 2009 8:37 pm
I don't understand how to get the answer to this one. I know the answer is 13, but it had a poor explanation. Please help.

On a soccer team consisting of 21 children, some of which are boys and some of which are girls, exactly of the boys and exactly of the girls attended the end of the season pizza party. What is the greatest number of children on the team who could have attended the party?

11
12
13
14
15
Zach
Top
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 90
Joined: Thu Aug 07, 2008 4:46 pm
Location: Toronto, Canada
Thanked: 3 times
GMAT Score:620

by rangerguy2000 » Wed Aug 12, 2009 8:41 pm
you are missing some important information in the qs? i think ur missing tha part of thing ...
Top
Master | Next Rank: 500 Posts
Posts: 399
Joined: Wed Apr 15, 2009 3:48 am
Location: india
Thanked: 39 times

by xcusemeplz2009 » Wed Aug 12, 2009 8:55 pm
pls post the exp
Top
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Thu Dec 18, 2008 9:51 pm
Location: San Diego, Ca

by properz » Wed Aug 12, 2009 9:37 pm
I copied and pasted the question. It has you guess the number of boys total, then guess how many girls would be considered 1/3. It's really confusing. I'm hoping for a better answer on here. The answer is 13.
Zach
Top
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Thu Dec 18, 2008 9:51 pm
Location: San Diego, Ca

oops, here's the missing info!!!

by properz » Wed Aug 12, 2009 9:37 pm
On a soccer team consisting of 21 children, some of which are boys and some of which are girls, exactly 2/3 of the boys and exactly 1/3 of the girls attended the end of the season pizza party. What is the greatest number of children on the team who could have attended the party?

11
12
13
14
15
Zach
Top
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

by tohellandback » Wed Aug 12, 2009 9:52 pm
the solution is more reasoning than calculation
since 2/3 boys attend the party and 1/3 girls attend the party
you would want to maximize the number of boys

girls should be at least 3 so that 1/3 *3 is a number.
so total 18 boys and 3 girls
2.3*18=12
1/3 *3=1
max 12+1=13 children can attend the party

girls number cannot be 0. because it is given the exactly 1/3 of girls attend the party.
The powers of two are bloody impolite!!
Top
Post new topic Post Reply
• Page 1 of 1