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Profit from the books

Expert replies
by psm12se » Mon Dec 09, 2013 6:50 am
A bookstore sells new books for $15 each and used books for $10 each. On every new book, the store makes a profit of $5 while on every used book it makes a profit of $2. If on a given day the bookstore's sales amounted to $125, which of the following cannot be the profit made on that day?

A. $27
B. $31
C. $35
D. $39
E. $41

OA: E

Please help the approach for this problem.
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Source: — Problem Solving |

by Brent@GMATPrepNow » Mon Dec 09, 2013 7:16 am
psm12se wrote:A bookstore sells new books for $15 each and used books for $10 each. On every new book, the store makes a profit of $5 while on every used book it makes a profit of $2. If on a given day the bookstore's sales amounted to $125, which of the following cannot be the profit made on that day?

A. $27
B. $31
C. $35
D. $39
E. $41
Let N = number of new books sold
Let U = number of used books sold

Sales:
If new books cost $15, and used books cost $10, then the total sales = 15N + 10U
We're told that the total sales is $125. So, we can write: 15N + 10U = 125
We can divide both sides by 5, to get a simpler equation: 3N + 2U = 25

Profits:
If the profit is $5 on new books, and $2 on used books, then the total profits = 5N + 2U

Let's take our two equations...
5N + 2U = profit
3N + 2U = 25
... and subtract the bottom equation from the top equation to get:
2N = profit - 25
Or...profit = 2N + 25

Interesting, on this given day, we can see that the profit equals 2N + 25.
Since N must be an integer, we can see that 2N must be even, in which case 2N+25 must be odd.
If we're lucky, there will be only 1 odd answer choice, in which case we can save a lot of time.
When I check the answer choices, I can see that all of the answer choices are odd. Too bad :-(

Okay, let's check the profits.
Answer choice A (the smallest answer choice) suggests that we could get a profit of $27.
Well, if 2N + 25 = profit, then we can write 2N + 25 = 27
When we solve for N, we get N=1.
We can plug N=1 into our equation 3N + 2U = 25 to get U=11.
Yep, that checks out.

Keep trying each answer choice, and you'll find that A, B, C and D are all possible.

Now let's check answer choice E (the biggest answer choice). It suggests that we could get a profit of $41.
Since 2N + 25 = profit, we can write 2N + 25 = 41
When we solve for N, we get N=8.
We can plug N=8 into our equation 3N + 2U = 25 to get U=0.5
This is impossible, so the answer is E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by GMATGuruNY » Mon Dec 09, 2013 7:16 am
A bookstore sells new books for $15 each and used books for $10 each. On every new book, the store makes a profit of $5 while on every used book it makes a profit of $2. If on a given day the bookstore's sales amounted to $125, which of the following cannot be the profit made on that day?

$27
$31
$35
$39
$41
15n + 10u = 125.

New books:
For the total amount of revenue to be ODD, 15n -- the revenue from the new books -- must also be ODD.
Each new book generates a profit of $5.
Thus, the following options are possible:
A: 15*1 = 15, profit = 1*5 = 5
B: 15*3 = 45, profit = 3*5 = 15
C: 15*5 = 75, profit = 5*5 = 25
D: 15*7 = 105, profit = 7*5 = 35.

Used books:
The BALANCE of the revenue comes for the $10 used books.
Each used book generates a profit of $2.
Thus, for the four options above, we get:
A: (125-15)/10 = 11, profit = 11*2 = 22
B: (125-45)/10 = 8, profit = 8*2 = 16
C: (125-75)/10 = 5, profit = 5*2 = 10
D: (125-105)/10 = 2, profit = 2*2 = 4.

Total profit for each option:

A = 5+22 = 27.
B = 15+16 = 31.
C = 25+10 = 35.
D = 35+4 = 39.

Since answer choices A, B, C and D are all possible, the correct answer is E.
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by Brent@GMATPrepNow » Mon Dec 09, 2013 7:19 am
I'd like to add that, whenever a GMAT math question requires me to check each answer choice, I typically start at E and work my way up to A.
It has been my experience that the test-makers like to place the correct answer closer to the bottom, because they know that most people start at the top and work their way down.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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