parasite8 wrote:Hi,

I have a question on inequalities with equations.

I tried using a strategy shown in Manhattan GMAT Prep - Guide 3 - Equations, Inequalities, & VICs on page 91 and 92.

When dividing the table states that divide and flip the extreme values. eg 8/LT2 = GT4 (if we know that LT2 is positive). Can I assume that if we do not know if LT2 is positive, then we can still divide and NOT flip or we just cannot divide to solve this question?

The reason I ask is because when I tried to solve: If b<2 and 2x-3b=0, which of the following must be true?
a. x>-3
b. x<2
c. x=3
d. x<3
e. x>3

I solved this by putting x to one side => x=(3b)/2
Then replaced "b" with LT2
x=(3LT2)/2
x=LT6/2
I wanted to divide here and x =GT3 (since I flipped the signs). My answer was incorrect and I want to know if I shouldn't have divided by 2 since I do not know if LT6 is positive or I should not have flipped the signs but can still divide.

(I ended up figuring it out a different way but I want to know why my original method did not work).

thanks,

Jen

parasite8 wrote:Hi,

I have a question on inequalities with equations.

I tried using a strategy shown in Manhattan GMAT Prep - Guide 3 - Equations, Inequalities, & VICs on page 91 and 92.

When dividing the table states that divide and flip the extreme values. eg 8/LT2 = GT4 (if we know that LT2 is positive). Can I assume that if we do not know if LT2 is positive, then we can still divide and NOT flip or we just cannot divide to solve this question?

The reason I ask is because when I tried to solve: If b<2 and 2x-3b=0, which of the following must be true?
a. x>-3
b. x<2
c. x=3
d. x<3
e. x>3

I solved this by putting x to one side => x=(3b)/2
Then replaced "b" with LT2
x=(3LT2)/2
x=LT6/2
I wanted to divide here and x =GT3 (since I flipped the signs)