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A case contains \(c\) cartons. Each carton contains \(b\) boxes, and each box contains \(100\) paper clips. How many

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A case contains \(c\) cartons. Each carton contains \(b\) boxes, and each box contains \(100\) paper clips. How many

by AAPL » Sun Jun 19, 2022 9:27 am

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A case contains \(c\) cartons. Each carton contains \(b\) boxes, and each box contains \(100\) paper clips. How many paper clips are contained in \(2\) cases?

A. \(100bc\)

B. \(\dfrac{100b}{c}\)

C. \(200bc\)

D. \(\dfrac{200b}{c}\)

E. \(\dfrac{200}{bc}\)

OA C
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Re: A case contains \(c\) cartons. Each carton contains \(b\) boxes, and each box contains \(100\) paper clips. How many

by Brent@GMATPrepNow » Tue Jun 21, 2022 6:44 am
AAPL wrote: ↑
Sun Jun 19, 2022 9:27 am
 Official Guide

A case contains \(c\) cartons. Each carton contains \(b\) boxes, and each box contains \(100\) paper clips. How many paper clips are contained in \(2\) cases?

A. \(100bc\)

B. \(\dfrac{100b}{c}\)

C. \(200bc\)

D. \(\dfrac{200b}{c}\)

E. \(\dfrac{200}{bc}\)

OA C
Let's solve using the INPUT-OUTPUT approach

Let b = 3 and c = 5
So, a case contains 5 cartons. Each carton contains 3 boxes, and each box contains 100 paper clips.
So, the number of paper clips in 1 case = (100)(5)(3) = 1500

How many paper clips are contained in 2 cases?
The number of paper clips in 2 cases = 3000

So, we're looking for the answer choice so that when we INPUT b = 3 and c = 5, we get an OUTPUT of 3000

Now check the answer choices:
(A) 100(3)(5) = 1500 ELIMINATE
(B) 100(3)/(5) = 60 ELIMINATE
(C) 200(3)(5) = 3000 KEEP!!
(D) 200(3)/(5) = 120 ELIMINATE
(E) 200/(3)(5) = 200/15 ELIMINATE

Answer: C
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Re: A case contains \(c\) cartons. Each carton contains \(b\) boxes, and each box contains \(100\) paper clips. How many

by Scott@TargetTestPrep » Fri Feb 10, 2023 5:27 am
AAPL wrote: ↑
Sun Jun 19, 2022 9:27 am
 Official Guide

A case contains \(c\) cartons. Each carton contains \(b\) boxes, and each box contains \(100\) paper clips. How many paper clips are contained in \(2\) cases?

A. \(100bc\)

B. \(\dfrac{100b}{c}\)

C. \(200bc\)

D. \(\dfrac{200b}{c}\)

E. \(\dfrac{200}{bc}\)

OA C
We are given that a case contains c cartons. Each carton contains b boxes, and each box contains 100 paper clips. Thus we can say the following:

c x b x 100 = 100bc paper clips per case

Thus, 2 cases would contain 2 x 100bc = 200bc paper clips.

Answer: C

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