datonman wrote:A closed cylindrical tank contains 36(pie) cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 4 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
A.)2
B.)3
C.)4
D.)6
E.)9
Volume of the water = 36Ï€.
Height of the water = 4 feet.
Since V = πr²h, we get:
36π = π(r²)(4)
9 = r²
r = 3.
Thus, the radius of the cylinder is 3 feet.
The water constitutes HALF the cylinder.
Implication:
When the tank is placed on its side, the water will rise HALFWAY up the base of the cylinder, as illustrated here:
https://www.physicsforums.com/threads/h ... me.206625/
Since halfway up the base of the cylinder is equal to the RADIUS of the cylinder, the height of the water will be 3 feet.
The correct answer is
B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3
