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At a restaurant, all tips are added together to be split among the employees at the end of a shift...

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by AAPL » Sat Jul 25, 2020 3:59 am

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At a restaurant, all tips are added together to be split among the employees at the end of a shift. The 4 waiters combined get 2/3 of the money, the manager receives 1/4, and the busboy receives the remainder. If 1 waiter and the busboy together receive $30, how much money was earned in tips for the entire shift?

A. $90
B. $96
C. $108
D. $120
E. $180

OA D
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Source: — Problem Solving |

Let total collected amount be X
Now waiters get = (2/3) X
So individual waiter gets: (2/3)X / 4 = X/6
Manager gets = X/4
Busboy gets = Total - waiters' share - manager's share = X - 2X/3 - X/4 = X/12

Now one waiter's share + busboy's share = X/6 + X/12 = X/4
X/4 is said to be $30
X/4 = 30
X = $120
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Let total tip be x, 4 Waiters(W) earn \(\frac{2x}{3}\) , Manger(M) \(\frac{x}{4}\) and busboy(B) remaining amount which will be \(\frac{x}{12}\)
Now Given 1 W +1 B = 30
4W = \(\frac{2x}{3}\) , so 1W= \(\frac{2x}{12}\)
\(\frac{2x}{12}\) + \(\frac{1x}{12}\) = 30

You will get x= 120.
OA: D
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