BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Need simpler logic!

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Legendary Member
Posts: 643
Joined: Wed Aug 14, 2013 4:27 amFollowed by: 7 members
Thanked: 48 times
by vinay1983 » Wed Sep 18, 2013 2:39 am
If k^3 is divisible by 240 what is the least possible value of integer K?

A. 12
B. 30
C. 60
D. 90
E. 120

The earlier answers were not understandable
You can, for example never foretell what any one man will do, but you can say with precision what an average number will be up to!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 468
Joined: Mon Jul 25, 2011 10:20 pmFollowed by: 4 members
Thanked: 29 times

by vipulgoyal » Wed Sep 18, 2013 2:45 am
k^3/2*2*2*2*3*5
k must have two 2 one 3 and one 5, hence smallest value = 60
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1556
Joined: Tue Aug 14, 2012 11:18 pmFollowed by: 34 members
Thanked: 448 times
GMAT Score:650

by theCodeToGMAT » Wed Sep 18, 2013 2:57 am
240= 2 x 3 x 2 x 2 x 5 x 2 == 2 ^ 4 x 3 x 5

hence, we would need a number that contains .. atleast TWO 2, one 3 and one 5.

The reason for TWO 2's is that if there were only one Two than cubing "k" would create only 2^3; but we need at least 2^4

So, Answer = 60 [C]

Hope this solution is understandable; feel free to ask if you have any doubts!!

Njoy!

vinay1983 wrote:If k^3 is divisible by 240 what is the least possible value of integer K?

A. 12
B. 30
C. 60
D. 90
E. 120

The earlier answers were not understandable
Last edited by theCodeToGMAT on Wed Sep 18, 2013 2:59 am, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760

by sanju09 » Wed Sep 18, 2013 2:58 am
vinay1983 wrote:If k^3 is divisible by 240 what is the least possible value of integer K?

A. 12
B. 30
C. 60
D. 90
E. 120

The earlier answers were not understandable
240 = 2^4 times 3^1 times 5^1, and the smallest cube number divisible by 240 must have 2 more 2s, 2 more 3s, and 2 more 5s to become 2^6 times 3^3 times 5^3, whose cube root (k here) is [spoiler]2^2 times 3^1 times 5^1 = 60.

Pick C[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Wed Sep 18, 2013 7:00 am
vinay1983 wrote:If k^3 is divisible by 240 what is the least possible value of integer K?

A. 12
B. 30
C. 60
D. 90
E. 120
The approach shown by vipulgoyal and rahulmittal87 is perfect, but if you didn't spot that approach, don't forget that we can also test the answer choices.

k^3 is divisible by 240
Since 240 = (2)(2)(2)(2)(3)(5), we know that k^3 MUST HAVE at least four 2's, one 3 and one 5 in its prime factorization.

Now check the answer choices.

A) k = 12 = (2)(2)(3)
Since there's no 5 in the prime factorization of k, k^3 cannot have at least one 5 in its prime factorization
ELIMINATE A.

B) k = 15 = (2)(3)(5)
So, k^3 = (2)(3)(5)(2)(3)(5)(2)(3)(5)
As we can see, k^3 does not have at least four 2's in its prime factorization
ELIMINATE B.

C) k = 30 = (2)(2)(3)(5)
So, k^3 = (2)(2)(3)(5)(2)(2)(3)(5)(2)(2)(3)(5)
Perfect! k^3 has at least four 2's, one 3 and one 5 in its prime factorization

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1