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OG 10 Q-102

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by shashank.ism » Sat Feb 20, 2010 11:29 am
TheGuest wrote:If T=5/9*(K - 32), and if T=290, then K=

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

Books states the answer is D but I got C.
T=5/9*(K - 32) , T=290
--> 290 = 5/9*(K - 32) --> 290 x5/9 = K-32 --> 522 = k-32 --> k = 554
Ans D ....its very simple..hope u understand..


please post ur solution ...I would rectify it...
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by TheGuest » Sat Feb 20, 2010 11:47 am
Well you got it wrong =) Not "290 x5/9" but "290/(5/9)"
I see what I did wrong here. I got K-32=522 instead of K=522+32 I did K=522-32. As always just need to pay attention to details.

Thanks,
TheGuest
shashank.ism wrote:
TheGuest wrote:If T=5/9*(K - 32), and if T=290, then K=

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

Books states the answer is D but I got C.
T=5/9*(K - 32) , T=290
--> 290 = 5/9*(K - 32) --> 290 x5/9 = K-32 --> 522 = k-32 --> k = 554
Ans D ....its very simple..hope u understand..


please post ur solution ...I would rectify it...
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by shashank.ism » Sat Feb 20, 2010 12:13 pm
TheGuest wrote:Well you got it wrong =) Not "290 x5/9" but "290/(5/9)"
I see what I did wrong here. I got K-32=522 instead of K=522+32 I did K=522-32. As always just need to pay attention to details.

Thanks,
TheGuest
shashank.ism wrote:
TheGuest wrote:If T=5/9*(K - 32), and if T=290, then K=

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

Books states the answer is D but I got C.
T=5/9*(K - 32) , T=290
--> 290 = 5/9*(K - 32) --> 290 x5/9 = K-32 --> 522 = k-32 --> k = 554
Ans D ....its very simple..hope u understand..


please post ur solution ...I would rectify it...
oh sorry guest I did a basic mistake it will be actually 290 = 5/9*(K - 32) --> 290 x9/5 = K-32 ...but ans is correct ...I did mistake in haste ..actually i m solving problem on lappy only without pen and paper...well thanks for pointing out the mistake..
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by Jeff@TargetTestPrep » Thu Apr 19, 2018 5:05 pm
TheGuest wrote:If T=5/9*(K - 32), and if T=290, then K=

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5
We start by substituting 290 for T and we obtain:

290 = 5/9(K - 32)

To eliminate the fraction, we multiply the entire equation by 9 and we have:

290 x 9 = 5(K - 32)

We next divide both sides by 5 and then solve for K:

58 x 9 = K - 32

522 = K - 32

554 = K

Answer: D

Jeffrey Miller
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