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Poker

by ov25 » Mon Dec 13, 2010 2:02 pm
Two cards selected from a pair of poker. If the sum of the numbers on the card is no more than 7, how many different possible values does the product of the two numbers have?

a) 7
b) 8
c)10
d) 12
e)14

My count is different from OA. Want some discussion around this.
OA C
Last edited by ov25 on Tue Dec 14, 2010 7:58 am, edited 1 time in total.
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by diebeatsthegmat » Tue Dec 14, 2010 7:19 am
ov25 wrote:Two cards selected from a pair of poker. If the sum of the numbers on the card is no more than 7, how many different possible values does the product of the two numbers have?

a) 7
b) 8
c)10
d) 12
e)14

My count is different from OA. Want some discussion around this.
is the answer D
i count it, took 2 min :(
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by ov25 » Tue Dec 14, 2010 8:00 am
Thanks Die. I got the same answer as yours. But the OA is different, as posted. May be experts can resolve
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by tomada » Tue Dec 14, 2010 11:56 am
I'm having trouble understanding the phrase "Two cards selected from a pair of poker". Poker is a card game, which can be played many different ways, some of which involve 5 cards, some involve 7 cards, etc. Can someone indicate the source of this question?
I'm really old, but I'll never be too old to become more educated.
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by Woozler » Tue Dec 14, 2010 12:12 pm
The question presupposes familiarity with card decks and indicates lack of familiarity with standard English on the part of the question writer. Definitely not a GMAT type question. Wherever you got this question, avoid this source in the future. Such blatant lack of professionalism indicates trouble.
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by diebeatsthegmat » Wed Dec 15, 2010 8:52 am
ov25 wrote:Two cards selected from a pair of poker. If the sum of the numbers on the card is no more than 7, how many different possible values does the product of the two numbers have?

a) 7
b) 8
c)10
d) 12
e)14

My count is different from OA. Want some discussion around this.
OA C
consider 2 cards are a and b
a+b< or = 7
its just the following number
1+6, 2+5,3+4
1+5, 2+4,3+3
1+4, 2+3
1+3,2+2
1+2,1+1
i cant understand whats wrong if the answer is C :(
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by goyalsau » Wed Dec 15, 2010 9:20 am
diebeatsthegmat wrote:
ov25 wrote:Two cards selected from a pair of poker. If the sum of the numbers on the card is no more than 7, how many different possible values does the product of the two numbers have?

a) 7
b) 8
c)10
d) 12
e)14

My count is different from OA. Want some discussion around this.
OA C
consider 2 cards are a and b
a+b< or = 7
its just the following number
1+6, 2+5,3+4
1+5, 2+4,3+3
1+4, 2+3
1+3,2+2
1+2,1+1
i cant understand whats wrong if the answer is C :(
OA has to be wrong.............
Saurabh Goyal
[email protected]
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EveryBody Wants to Win But Nobody wants to prepare for Win.
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by lfaridia » Wed Dec 15, 2010 2:25 pm
Question is asking: How many "diffrent" possible values does the product of the two numbers have?
Possibilities are:
1*6=6
2*5=10
3*4=12
1*5=5
2*4=8
3*3=9
1*4=4
2*3=6 (Duplicate)
1*3=3
2*2=4 (Duplicate)
1*2=2
1*1=1

The answer is: 10 (C)
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