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thumpin_termis
- Senior | Next Rank: 100 Posts
- Posts: 60
- Joined: Fri Jun 01, 2007 11:02 pm
Problem 1:
If both cold and hot leak together (t), the time taken would be less
than either cold (c) or hot (h).
So, we can form the inequality 0 < t < c < h
We can hence conclude I is true and II is false
If c = h, then t = c/2 = h/2. But we know c < h, so t has to be > c/2 and
less than h/2. So, III is true.
So, E -- I and III only.
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Problem 2:
(1001+999)(1001-999) / (101+99)(101-99)
= 2000*2 / 200*2
= 10
