Carl averaged 2m miles per hour on a trip that took

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BTGModeratorVI wrote:
Tue Mar 03, 2020 6:35 am
Carl averaged 2m miles per hour on a trip that took him h hours. If Ruth made the same trip in 23h23h hours, what was her average speed in miles per hour?

A. 1/3 mh
B. 2/3 mh
C. m
D. 3m/2
E. 3m

Answer: E
Source: Official Guide
Carl averaged 2m miles per hour on a trip that took him h hours
distance = (rate)(time)
So, Carl's travel distance = (2m)(h) = 2mh

If Ruth made the same trip in 2h/3 hours, what was her average speed in miles per hour?
average speed = distance/time
So, Ruth's average speed = (2mh)/(2h/3)
= (2mh)(3/2h)
= 6m/2
= 3m

Answer: E

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BTGModeratorVI wrote:
Tue Mar 03, 2020 6:35 am
Carl averaged 2m miles per hour on a trip that took him h hours. If Ruth made the same trip in 23h23h hours, what was her average speed in miles per hour?

A. 1/3 mh
B. 2/3 mh
C. m
D. 3m/2
E. 3m

Answer: E
Source: Official Guide
We have the formula: \(\text{Speed}=\dfrac{\text{Distance}}{\text{Time}}\)

Now, for Carl we have:

Speed \(= 2\)m miles/hour

Time \(= h\) hours

Therefore, \(\text{Distance} = \text{Speed} \cdot \text{Time} = 2m \cdot h = 2mh\) miles.

For Ruth we have:

Distance = Same as that of Carl \(= 2mh\) miles

Time \(= \dfrac{2}{3}h\)

Hence, \(\text{Speed} = \dfrac{\text{Distance}}{\text{Time}} = \dfrac{2mh}{2h/3} = 3m\) miles/hour.

So, the correct answer is E

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BTGModeratorVI wrote:
Tue Mar 03, 2020 6:35 am
Carl averaged 2m miles per hour on a trip that took him h hours. If Ruth made the same trip in 23h23h hours, what was her average speed in miles per hour?

A. 1/3 mh
B. 2/3 mh
C. m
D. 3m/2
E. 3m

Answer: E
Source: Official Guide
The distance of the trip is 2mh.

So Ruth’s average speed was:

2mh/(2h/3) = 6mh/2h = 6m/2 = 3m

Answer: E

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