Q. If the sum of the consecutive integers from -22 to x, inclusive 72, what is the Value of x?
a. 23 b. 25. c. 50 d.75 e. 94
a. 23 b. 25. c. 50 d.75 e. 94
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We know that (-22) + (-21) + (-20) + . . . 0 . . . + 20 + 21 + 22 will equal zero, since (-22) + 22 = 0, (-21) + 21 = 0, (-20) + 20 = 0, etc.Joy Shaha wrote:Q. If the sum of the consecutive integers from -22 to x, inclusive 72, what is the Value of x?
a. 23 b. 25. c. 50 d.75 e. 94
Couldn't have said it better myselfdanielle07 wrote:We will cancel all the negative integers and know that the sum -22 + -21 + .. + 0 + .. + 21 + 22 which is 0.
Then we will start adding on the next but 23 + 24 isn't enough to get 72, so we will add the next digit 23 + 24 + 25 is equal to 72. That's how we will get the answer.
Answer: B
The quantity is x - (-22) + 1 = x + 23.Joy Shaha wrote:Q. If the sum of the consecutive integers from -22 to x, inclusive 72, what is the Value of x?
a. 23 b. 25. c. 50 d.75 e. 94

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