Let t� = the time for the first 320 miles and t₂ = the time for the second 320 miles.
Since the first half of the trip is traveled at 80mph, t� = d/r = 320/80 = 4 hours.
Since Mike takes 200% LONGER to travel the remaining 320 miles, t₂ = t� + 200% of t� = 4 + (200/100)(4) = 4 + 8 = 12.
Average speed = (total distance)/(total time) = 640/(4+12) = 40mph.
The correct answer is C.
Last edited by
GMATGuruNY on Thu Jun 19, 2014 10:47 am, edited 1 time in total.
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