If t= 1/(2^9 * 5^3) is expressed as a terminating decimal, how many zeros will t have between the decimal point and the first non zero digit to the right of the decimal point?
A - THREE
B - FOUR
C - FIVE
D - SIX
E - NINE
Determine how many powers of 10 are in the denominator.
1/(2�*5³) = 1 / (2�)(2³*5³) = 1/(64*10³) = 1/64,000.
There are four 0's to the right of the decimal.
The correct answer is
B.
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