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Source: — Data Sufficiency |
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by vikram4689 » Thu Jun 16, 2011 1:22 am
please post the full equation, inequalities cannot be solved unless limits on the variables are not known
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by divya23 » Thu Jun 16, 2011 1:26 am
this is the full question nothing else was given
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by Frankenstein » Thu Jun 16, 2011 1:46 am
Hi,
From(1): x^2+y^2>z^2
if x=3, y=3, z=4 x^4+y^4 = 162 < z^4(256)
if x=2, y=2, z= 1 x^4+y^4>z^4
Not sufficient

From(2):
if x=3, y=3, z=4 x^4+y^4 = 162 < z^4(256)
if x=2, y=2, z= 1 x^4+y^4>z^4
Not sufficient

Both (1)&(2): Use the same set of values as those used in (1)&(2)
Not sufficient

Hence, E
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by vikram4689 » Thu Jun 16, 2011 1:54 am
divya23 wrote:this is the full question nothing else was given
Well in that case i think answer would always be E because even if we are able to get some consistency bu putting values, we can always reverse values of x,y & z to get the opposite result.
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by amit2k9 » Fri Jun 17, 2011 6:06 am
observe that the exponents here are even.Hence we need not try negative values.

checking for 1,1,1 and 1,2,2.

a for 1,1,1 LHS=RHS. for 1,2,2 LHS > RHS. not sufficient.

b same as above. not sufficient.

a+b not sufficient.

E it is.
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by Frankenstein » Fri Jun 17, 2011 6:19 am
amit2k9 wrote:
a for 1,1,1 LHS=RHS. for 1,2,2 LHS > RHS. not sufficient.
For 1,1,1 LHS(2) > RHS(1).
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