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Mean Even?

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by kanha81 » Tue Jun 30, 2009 8:08 pm
For a set X containing n integers, is the mean even?

(1) n is even.

(2) All of the integers in set X are even.

My Approach:
1) even number of integers, BUT no information pertaining to the spacing between the integers ie. consecutive or evenly spaced.

Insuff

2) integers are multiples of two, BUT no information pertaining to the number of integers ie. even number of integers or odd number of integers

Even number of integers: AM (X) = odd
Odd number of integers: AM (X) = even

Insuff

1) & 2) integers are multiples of two and even number of integers

AM (X) = odd

Suff

What's wrong?
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Source: — Data Sufficiency |

by aj5105 » Tue Jun 30, 2009 8:41 pm
Statement (2) alone is sufficient.

Ex:

(2 + 2 + 2 )/3 = 2 (even)

(2 + 2)/2 = 2 (even)
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by tohellandback » Tue Jun 30, 2009 10:30 pm
aj5105 wrote:Statement (2) alone is sufficient.

Ex:

(2 + 2 + 2 )/3 = 2 (even)

(2 + 2)/2 = 2 (even)
and how about(4,4,2)??
The powers of two are bloody impolite!!
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by aj5105 » Wed Jul 01, 2009 3:00 am
annoying!

(E)
tohellandback wrote:
aj5105 wrote:Statement (2) alone is sufficient.

Ex:

(2 + 2 + 2 )/3 = 2 (even)

(2 + 2)/2 = 2 (even)
and how about(4,4,2)??
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by rahulg83 » Wed Jul 01, 2009 3:05 am
aj5105 wrote:annoying!

(E)
tohellandback wrote:
aj5105 wrote:Statement (2) alone is sufficient.

Ex:

(2 + 2 + 2 )/3 = 2 (even)

(2 + 2)/2 = 2 (even)
and how about(4,4,2)??
Yes E should be the answer, mean can be a fraction value, even if yo consider both the statements. :)
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