BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

P&C

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 91
Joined: Fri Jan 17, 2014 7:34 am
Thanked: 7 times
by parveen110 » Sun Jan 19, 2014 4:57 am
The number of all possible selections which a student can make for answering one or more questions out of 10 given questions in a paper, when each question has an alternative is:
a. 1345
b. 23560
c. 541340
d. 59048
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pmFollowed by: 511 members
Location: Palo Alto, CA
Thanked: 2867 times
GMAT Score:800

by [email protected] » Sun Jan 19, 2014 4:15 pm
Hi parveen110,

This is NOT a GMAT question and also happens to be poorly worded. It is unclear what the phrase "each question has an alternative" means. If the question asked for "the number of combinations of questions that could be answered if at last one question was answered", then this would be a multi-step combinatorics question (and would require several small calculations).

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 91
Joined: Fri Jan 17, 2014 7:34 am
Thanked: 7 times

by parveen110 » Sun Jan 19, 2014 8:32 pm
[email protected] wrote:Hi parveen110,

This is NOT a GMAT question and also happens to be poorly worded. It is unclear what the phrase "each question has an alternative" means. If the question asked for "the number of combinations of questions that could be answered if at last one question was answered", then this would be a multi-step combinatorics question (and would require several small calculations).

GMAT assassins aren't born, they're made,
Rich


Hi Rich,

Thanks for the reply.However, This question doesn't involve multi-step combinatorics. And the phrase "each question has an alternative" means that each question has two choices and out of which only one can be chosen.

I have a solution which i'm little confused about. Here it goes:

Each question can be attempted in three ways:
1. The student do not solve the question.
2. The student attempts first part of the question.
3. The student attempts the second(i.e.,alternative) part of the question.

Therefore required number of ways= 3^10-1=59048.

My confusion regarding the solution part is:

Can i not solve it in a following way:

The student may select 1 question out of 10 in 10C1 ways.

The student may select 2 question out of 10 in 10C2 ways.

and so on...
Finally the student may select 10 questions out of 10 in 10C10 ways.

Adding all the possibilities up:

(10C0+10C1+10C2+10C3+10C4+....+10C10) = 2^10 = 1024

Now since each question has an alternative, I multiply the above step by 2= 2 x 1024
=4028 ways.
Now since according to the question, i have to attempt at least 1 question,
I may do so in 4028-1 = 4027 ways.

I just would like to know where is this approach flawed. Am i making not accounting for something by multiplying the possibilities by 2?

Hope I've made myself amply clear:)

Thanks.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1