OG Quant Review #82

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480ocean: Junior | Next Rank: 30 Posts; Posts: 26; Joined: Mon Oct 27, 2008 1:01 pm; Thanked: 1 times

by 480ocean » Sun Feb 15, 2009 1:04 pm

If m and n are consecutive positive integers, is m greater than n?
1. m-1 and n+1 are consecutive positive integers.
2. m is an even integer.

Answer is A

Thanks for your help!

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Source: Beat The GMAT — Data Sufficiency | Sun Feb 15, 2009 1:04 pm

cramya: Legendary Member; Posts: 2467; Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members; Thanked: 331 times

by cramya » Sun Feb 15, 2009 1:36 pm

Take easier of the the two

Stmt II

No info about n .INSUFF

Stmt I

Lets assume that:
The order can be mn(m<n) or nm((m>n)

If its mn then m-1 and n+1 can never be consecutive. Therefore it has to be nm where m-1 (i.e. n) and n+1 (i.e m) are again conseutive satisfying Stmt I

SUFF

Hence A

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Bidisha800: Master | Next Rank: 500 Posts; Posts: 344; Joined: Sun Sep 28, 2008 11:00 amFollowed by: 1 member; Location: USA; Thanked: 6 times

by Bidisha800 » Sun Feb 15, 2009 2:03 pm

m-1 and n+1 are consecutive ,

therefore, either (m-1) + 1= (n+1) OR m-1 = (n+1) +1

if (m-1) + 1= (n+1)

m= n+1

therefore, m>n

if m-1 = (n+1) +1

m = n +3

m>n

(A) suff

(B) is insuff

Drill baby drill !

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480ocean: Junior | Next Rank: 30 Posts; Posts: 26; Joined: Mon Oct 27, 2008 1:01 pm; Thanked: 1 times

by 480ocean » Mon Feb 16, 2009 2:08 pm

Got it! Thank you for your help!

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